Solution: find the middle element of the string. Check to see if rule 1 n 2 applies to the string expanding from the middle element and return 1 if found or 0 if not found. then recursively call the left and right substring without the middle element and add all elements the match into the counter. return the counter
vcdcd. ( check if d, cdc, vcdcd are valid )
vc (check v and _vc are valid) cd (check d, _dc are valid)
(check c) (check d)


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